(x^2-3x+2)/(x^2+9x+20)/(x-2)/(x+4)

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Solution for (x^2-3x+2)/(x^2+9x+20)/(x-2)/(x+4) equation: 


D( x )

x+4 = 0

x-2 = 0

x^2+9*x+20 = 0

x+4 = 0

x+4 = 0

x+4 = 0 // - 4

x = -4

x-2 = 0

x-2 = 0

x-2 = 0 // + 2

x = 2

x^2+9*x+20 = 0

x^2+9*x+20 = 0

x^2+9*x+20 = 0

DELTA = 9^2-(1*4*20)

DELTA = 1

DELTA > 0

x = (1^(1/2)-9)/(1*2) or x = (-1^(1/2)-9)/(1*2)

x = -4 or x = -5

x in (-oo:-5) U (-5:-4) U (-4:2) U (2:+oo)

(((x^2-(3*x)+2)/(x^2+9*x+20))/(x-2))/(x+4) = 0

(((x^2-3*x+2)/(x^2+9*x+20))/(x-2))/(x+4) = 0

(x^2-3*x+2)/((x^2+9*x+20)*(x-2)*(x+4)) = 0

x^2-3*x+2 = 0

x^2-3*x+2 = 0

DELTA = (-3)^2-(1*2*4)

DELTA = 1

DELTA > 0

x = (1^(1/2)+3)/(1*2) or x = (3-1^(1/2))/(1*2)

x = 2 or x = 1

(x-1)*(x-2) = 0

x^2+9*x+20 = 0

x^2+9*x+20 = 0

DELTA = 9^2-(1*4*20)

DELTA = 1

DELTA > 0

x = (1^(1/2)-9)/(1*2) or x = (-1^(1/2)-9)/(1*2)

x = -4 or x = -5

(x+5)*(x+4) = 0

(x-1)/((x+5)*(x+4)^2) = 0

x-1 = 0 // + 1

x = 1

x = 1

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